阿川CH

ImmutableSet<String> digits = ImmutableSet.of("zero", "one", "two", "three", "four",
  "five", "six", "seven", "eight", "nine");
Function<String, Integer> lengthFunction = new Function<String, Integer>() {
  public Integer apply(String string) {
    return string.length();
  }
};
ImmutableListMultimap<Integer, String> digitsByLength = Multimaps.index(digits, lengthFunction);
/*
* digitsByLength maps:
*  3 => {"one", "two", "six"}
*  4 => {"zero", "four", "five", "nine"}
*  5 => {"three", "seven", "eight"}
*/

ArrayListMultimap<String, Integer> multimap = ArrayListMultimap.create();
multimap.putAll("b", Ints.asList(2, 4, 6));
multimap.putAll("a", Ints.asList(4, 2, 1));
multimap.putAll("c", Ints.asList(2, 5, 3));

TreeMultimap<Integer, String> inverse = Multimaps.invertFrom(multimap, TreeMultimap.<String, Integer> create());
// note that we choose the implementation, so if we use a TreeMultimap, we get results in order
/*
* inverse maps:
*  1 => {"a"}
*  2 => {"a", "b", "c"}
*  3 => {"c"}
*  4 => {"a", "b"}
*  5 => {"c"}
*  6 => {"b"}
*/

Map<String, Integer> map = ImmutableMap.of("a", 1, "b", 1, "c", 2);
SetMultimap<String, Integer> multimap = Multimaps.forMap(map);
// multimap maps ["a" => {1}, "b" => {1}, "c" => {2}]
Multimap<Integer, String> inverse = Multimaps.invertFrom(multimap, HashMultimap.<Integer, String> create());
// inverse maps [1 => {"a", "b"}, 2 => {"c"}]